What is the probability of rolling at least a 4 on a die?
Two (6-sided) dice roll probability table
What is the probability that at least one die shows a 4?
P(B) = 6 36 . Now, if the first die shows 4 there is only one way to make the sum of both dice equal 7 which means P(A ∩ B) = 1 36 . Therefore, the probability that the first die shows 4 given that the sum is 7 is P(A|B) = P(A ∩ B) P(B) = 1/36 6/36 = 1 6 .
What is the probability that at least one of the three dice is a 4?
Outcomes containing at least one occurrence of 4 when rolling 3 dice: Therefore, 91 of the 216 possible 3 dice roll outcomes contain at least one (4).
What is the probability of getting at least one 4 in a roll of two dice?
= 1/36 for showing at least a 4 in two dice. Therefore, the probability of tossing two dice and showing at least one 4 is 11/36.
What is the probability of getting at least one 6?
a) Consider the complement problem, there is a 5/6 probability of not rolling a six for any given die, and since the four dice are independent, the probability of not rolling a six is (5/6)4 = 54/64 = 625/1296. The probability of rolling at least one six is therefore 1 − 625/1296 = 671/1296 ≈ .
How do you find the probability of at least?
To find the probability of at least one of something, calculate the probability of none and then subtract that result from 1. That is, P(at least one) = 1 – P(none).
What is the probability that at least one die is a 3?
In 25/36 rolls there are no threes. Therefore in 11/36 rolls, or 31%, will be at least one three.
What is the probability of having at least one six from 3 throws of a perfect die?
Question: What is the probability of getting at least one six in a single throw of three unbiased dice? Answer: The probability of getting either 1 or 2 or 3 or 4 or 5 when one dice is thrown is 5/6 x 5/6 x 5/6 for 3 dices = 125/216. This is the probability of getting at lease one 6 when 3 dices are thrown.
What is the probability of throwing 6 with a dice at least once in 3 attempts?
Therefore the answer is 91/216. Hope this helps!