Your question: When two dice are thrown find the probability of getting a total of 15?

Probability of a sum of 15: 10/216 = 4.6% Probability of a sum of 16: 6/216 = 2.8% Probability of a sum of 17: 3/216 = 1.4% Probability of a sum of 18: 1/216 = 0.5%

What is the probability of getting a sum of 15 when two dice are thrown?

So, the number of favourable outcomes =1+2+4+6+2=15. We know that the number of possible outcomes is 36. Thus, the probability of getting the sum of two numbers as prime numbers is =1536=512. (b) We will now calculate the probability of occurrence of a doublet of an even number.

When two dice are thrown the probability of getting the sum?

Answer: The probability of rolling two dice and getting a sum of 4 is 1/12. Let’s find how likely we get a sum of 4 when we roll two dice simultaneously. So, when we roll two dice there are 6 × 6 = 36 possibilities.

What is the probability of getting the sum of 9 from two thrown dice?

What is the probability of getting a sum 9 from two throws of a dice? Explanation: In two throws of a dice, n(S) = (6 x 6) = 36.

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What is the probability of getting a sum as 3 If a dice is thrown * 1 point?

probability of getting sum as 3 = 1/18

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What is the probability of spinning an even number?

The probability of getting an even number on spinning the wheel is 1/2 and that of a prime number is 4/6.

What is the probability of getting 1 and 5 If a dice is thrown once?

So they are mutually exclusive events, therefore their probabilities add to 1. By symmetry we expect that each face is equally likely to appear and so each has probability = 1/6. The outcome of a 5 is one of those events and so has probability = 1/6 of appearing.

What will be the probability of getting odd numbers if a dice is thrown?

Hence, the required probability of getting an odd number , P(E) = 1/2.

What is the probability of getting the same number on two dice?

When two dice are drawn there will be 36 combinations. However, for getting the same number on both die, there will be 6 possibilities which are (1,1),(2,2),(3,3),(4,4),(5,5) and (6,6). Hence, the required probability is 6/36 = 1/6.

What is the probability of rolling a sum of 7 and 11?

What is the probability that the sum will be a 7 or 11? There are 36 possible outcomes for the two dice. So, the probability is 8/36 = 2/9.

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