Question: What is the probability of getting at least one six in a single throw of three unbiased dice? Answer: The probability of getting either 1 or 2 or 3 or 4 or 5 when one dice is thrown is 5/6 x 5/6 x 5/6 for 3 dices = 125/216. This is the probability of getting at lease one 6 when 3 dices are thrown.

## What is the probability of getting at least one 6 when 3 dice are rolled?

So, there are 125 out of 216 chances of a 6 NOT appearing when three dice are rolled. Simply subtract 125 from 216 which will give us the chances a 6 WILL appear when three dice are rolled, which is **91**. 91 out of 216 or 42.1 %.

## What is the probability of rolling at least one six on single toss of a pair of fair dice?

1 – 125/216 = 91/216 or approx **42%**. So, the required probability of getting at least one 6 is . Assuming a 6 faced standard die, unbiased as you said, the probability that it doesn’t roll a 6 = 5/6.

## What is the probability of having at least one six from 3 throws of a perfect diet?

Originally Answered: what is the probability of having at least one 6 from three throws of a perfect die? The probability of getting 6 for single through is 1/6. for three throw it will be 3*1/6 = **1/2**.

## What is the probability of rolling at least one 4?

Probability of rolling a certain number or less with one die

Roll a…or less | Probability |
---|---|

3 | 3/6 (50.000%) |

4 | 4/6 (66.667%) |

5 | 5/6 (83.333%) |

6 | 6/6 (100%) |

## What is the probability of getting three dots?

Probability of 3 dots lying on the same edge = 4*(1/4)^3 = **1/16** Probability of 2 dots lying on same edge with another on a different edge =4*[(1/4)^2]*(3/4) = 3/16 Probability dots lie on distinct edges = 4*(1/4)(3/4)(2/4) = 6/16 These 3 events only sum up to 10/16.

## How do you find the probability of at least?

To find the probability of at least one of something, calculate **the probability of none and then subtract that result from 1**. That is, P(at least one) = 1 – P(none).

## What is the probability of 4 out of 6?

There is a **40.00 percent probability** of a particular outcome and 60.00 percent probability of another outcome. If you bet 1 on a game with 4 to 6 odds and you win, your total payout will be 1.67 which is your bet plus 0.67 profit. Note that odds and probability are not the same.

## What is the probability of getting one?

Answer: The probability of getting 1 after rolling a die is **1 / 6**.

## What is the probability of rolling at least one 5?

So the probability of rolling at least one 5 is **1–(8/9)^6 = .** **5067+**. The number of possible outcomes which have atleast 1–5, is 6+6 (1×6, and 6×1, meaning one dice gets 5 and other dice 6 different numbers and vice versa). The total possible outcomes are 6×6 I.e. 36.

## What is the probability of rolling at least one 1 with two dice?

Since there are six possible outcomes, the probability of obtaining any side of the die is **1/6**. The probability of rolling a 1 is 1/6, the probability of rolling a 2 is 1/6, and so on.

## What is the probability of rolling at least one six in four rolls?

So the probability of rolling no 6’s with 4 fair die, is (5/6)^4. Therefore, the probability of rolling at least one 6 in 4 rolls (the complement), is 1-(5/6)^4 = **51.775%**.